A particle of mass m 1 is moving with a velocity v 1 and another particle of mass m 2 is moving with a velocity v 2 . Both of them have the same momentum but their different kinetic energies are E 1 and E 2 respectively. If m 1 > m 2 then :
A
E 1 < E 2
B
= 
C
E 1 > E 2
D
E 1 = E 2
Text Solution
Verified by ExpertsThe correct answer is:
A
Kinetic energy is given by
E = 
mv 2 = 
(mv) 2
but mv = momentum of the particle = p
∴ E = 
or p = 
Therefore, 
= 
but it is given that, p 1 = p 2
∴ m 1 E 1 = m 2 E 2
or 
= 
....(i)
Now m 1 > m 2
or 
> 1 ....(ii)
Thus, Eqs. (i) and (ii) give
< 1
or E 1 < E 2 .
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